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Sagot :
To determine the correct model for predicting the number of toys produced over time given the initial production and the rate of increase, we'll break down the problem step-by-step.
1. Understand the Initial Values and Growth Rate:
- Initial production is [tex]\(1,250,000\)[/tex] toys per year.
- This can be expressed as [tex]\(1.25\)[/tex] million toys, for simplicity in our model.
- The production increases by [tex]\(150\%\)[/tex] each year. A [tex]\(150\%\)[/tex] increase means the production grows to [tex]\(250\%\)[/tex] of the initial value each year because [tex]\(100\% + 150\% = 250\%\)[/tex].
2. Convert the Increase Rate to a Multiplier:
- A [tex]\(250\%\)[/tex] growth means that each year the production is multiplied by [tex]\(2.5\)[/tex].
3. Formulate the Exponential Growth Model:
- The general formula for exponential growth is [tex]\( n(t) = n_0 \cdot a^t \)[/tex] where:
[tex]\( n(t) \)[/tex] is the amount after [tex]\( t \)[/tex] years.
[tex]\( n_0 \)[/tex] is the initial amount.
[tex]\( a \)[/tex] is the growth factor per time period.
[tex]\( t \)[/tex] is the number of time periods (years in this case).
- For this problem:
[tex]\( n_0 = 1.25 \)[/tex] million (the initial production in millions).
The growth factor [tex]\( a = 2.5 \)[/tex].
4. Substitute the Given Values into the Model:
- Replacing [tex]\( n_0 \)[/tex] and [tex]\( a \)[/tex] in the model, we get [tex]\( n(t) = 1.25 \cdot 2.5^t \)[/tex].
5. Check the Options Provided:
- The model [tex]\( n = 1.25 \cdot 2.5^t \)[/tex] matches our derived formula.
Therefore, the correct model to find the number of toys [tex]\( n \)[/tex] (in millions) being produced in [tex]\( t \)[/tex] years is:
[tex]\[ n = 1.25 \cdot 2.5^t \][/tex]
1. Understand the Initial Values and Growth Rate:
- Initial production is [tex]\(1,250,000\)[/tex] toys per year.
- This can be expressed as [tex]\(1.25\)[/tex] million toys, for simplicity in our model.
- The production increases by [tex]\(150\%\)[/tex] each year. A [tex]\(150\%\)[/tex] increase means the production grows to [tex]\(250\%\)[/tex] of the initial value each year because [tex]\(100\% + 150\% = 250\%\)[/tex].
2. Convert the Increase Rate to a Multiplier:
- A [tex]\(250\%\)[/tex] growth means that each year the production is multiplied by [tex]\(2.5\)[/tex].
3. Formulate the Exponential Growth Model:
- The general formula for exponential growth is [tex]\( n(t) = n_0 \cdot a^t \)[/tex] where:
[tex]\( n(t) \)[/tex] is the amount after [tex]\( t \)[/tex] years.
[tex]\( n_0 \)[/tex] is the initial amount.
[tex]\( a \)[/tex] is the growth factor per time period.
[tex]\( t \)[/tex] is the number of time periods (years in this case).
- For this problem:
[tex]\( n_0 = 1.25 \)[/tex] million (the initial production in millions).
The growth factor [tex]\( a = 2.5 \)[/tex].
4. Substitute the Given Values into the Model:
- Replacing [tex]\( n_0 \)[/tex] and [tex]\( a \)[/tex] in the model, we get [tex]\( n(t) = 1.25 \cdot 2.5^t \)[/tex].
5. Check the Options Provided:
- The model [tex]\( n = 1.25 \cdot 2.5^t \)[/tex] matches our derived formula.
Therefore, the correct model to find the number of toys [tex]\( n \)[/tex] (in millions) being produced in [tex]\( t \)[/tex] years is:
[tex]\[ n = 1.25 \cdot 2.5^t \][/tex]
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