Answered

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Find the ordered pair that solves this by the elimination method. 1/5x +y = 6/5 and 1/10x + 1/3 y = 7/10

Sagot :

We already know that the solution is (9, -3/5), let's show that

[tex]\frac{1}{10}x+\frac{1}{3}y=\frac{7}{10}[/tex]

Let's plug our solution into the equation

[tex]\begin{gathered} \frac{1}{10}\cdot9+\frac{1}{3}\cdot(-\frac{3}{5})=\frac{7}{10} \\ \\ \frac{9}{10}-\frac{3}{15}=\frac{7}{10} \\ \\ \frac{9\cdot15-3\cdot10}{10\cdot15}=\frac{7}{10} \\ \\ \frac{135-30}{150}=\frac{7}{10} \\ \\ \frac{105}{150}=\frac{7}{10} \\ \\ \frac{21}{30}=\frac{7}{10} \\ \\ \boxed{\dfrac{7}{10} =\dfrac{7}{10} } \end{gathered}[/tex]

The second equation is true!

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