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Sagot :
Probability of an even number product as requested = 7/10 = .7 = 70%
The probability is the ratio of the number of outcomes in an exhaustive set of equally likely outcomes that produce a given event to the total number of possible outcomes.
A prime number is a whole number greater than 1 whose only factors are 1 and itself. A factor is a whole number that can be divided evenly into another number. The first few prime numbers are 2, 3, 5, 7, 11, 13, 17, 19, 23, and 29.
Combinations of 2 digits from among 5 = 5!/(3!)(2!) = 10. Those combinations of 2 digits resulting in an even number product are even*even and even*odd. There are 2 even digits, (2,4), and 3 odd digits, (1,3,5).
Combinations of 2 even digits and 3 odd digits = 3*2 = 6. Combinations of 2 even digits = 1*1 = 1. there are thus 6+1 = 7 distinct 2 digit products that result in even numbers from among 10 possible 2 digit products.
Probability of an even number product as requested = 7/10 = .7 = 70%
For more information on probability click on the link below:
https://brainly.com/question/25870256
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