Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

quadriatic formula 2w^2-28w=-98

Sagot :

222916
2w^2-28w=-98
w^2-14w+49=0D=14^2-4*49=0
w=(14+0)/2=7


RedRicin
To apply the quadratic formula, the right side must be equal to 0.

[tex]2w^2-28w=-98 \\ 2w^2-28w+98=0[/tex]

Now you can apply the quadratic formula [tex]\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex] to find the solution for w.

[tex]\frac{-(-28)\±\sqrt{(-28)^2-4(2)(98)}}{2(2)} = \frac{28\±\sqrt{784-784}}{4} = \frac{28}4 = \boxed{7} [/tex]

(The quadratic formula is highly unnecessary in this problem, however. You could easily divide all values by 2 to get w²-14w+49=0, which factors into (w-7)²=0, for which 7 is the only solution which puts a factor of the quadratic equal to 0.)


Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.