Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
The volume occupied by 22. 0 g of helium gas at 26. 0 ° C and 1. 20 atm of pressure is 112.37 L .
Calculation ,
According to ideal gas equation ,
PV = nRT ....(i)
where P is the pressure = 1. 20 atm
V is the volume of the helium gas = ?
R is the universal gas constant = 0.082 atm L /K mol
T is the temperature of the gas = 26. 0 ° C = 299 K
n is the number of moles
Number of miles (n) = given mass/ molar mass =22 g/4 = 5.5 moles
By putting the value of pressure , volume , temperature and universal gas constant in equation ( i) we get
1. 20 atm ×V = 5.5 moles × 0.082×299
V = 5.5 moles × 0.082×299/1. 20 atm = 112.37 L
To learn more about helium gas please click here ,
https://brainly.com/question/13645498
#SPJ4
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.
