Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Find the probability that when a couple has ​children, at least one of them is a . ​(Assume that boys and girls are equally​ likely.)

Sagot :

MrRoyal

Answer:

[tex]P(At\ least\ one\ girl) = 0.875[/tex]

Step-by-step explanation:

Given

[tex]n = 3[/tex]

[tex]B \to boys[/tex]

[tex]G \to girls[/tex]

[tex]P(G) = P(B) = 0.5[/tex] --- equal probability

See comment for complete question

Required:

[tex]P(At\ least\ one\ girl)[/tex]

To do this, we make use of complement rule:

[tex]P(At\ least\ one\ girl) = 1 - P(No\ girl)[/tex]

The event that there is no girl out of the 3 children is: B B B

And the probability is:

[tex]P(No\ Girl) = P(B) * P(B) * P(B)[/tex]

[tex]P(No\ Girl) = 0.5*0.5*0.5[/tex]

[tex]P(No\ Girl) = 0.125[/tex]

So:

[tex]P(At\ least\ one\ girl) = 1 - P(No\ girl)[/tex]

[tex]P(At\ least\ one\ girl) = 1 - 0.125[/tex]

[tex]P(At\ least\ one\ girl) = 0.875[/tex]

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.