Answered

Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

In circle B below, diameter RT, radius BE, and chord RE are drawn.
If m2TRE = 15° and BE = 9, then the area of sector EBR is

Sagot :

akposevictor

The area of sector EBR in the given diagram attached below is: 33.75π units².

What is the Area of a Sector?

Area = θ/360º × πr²

Given the following:

  • m∠TRE = 15°
  • BE = 9

Measure of arc TE = 2(m∠TRE) = 2(15) [inscribed angle theorem]

Measure of arc TE = 30°

Arc RE = 180 - arc TE = 180 - 30 [semicircle]

Arc RE = 150°

m∠EBR = Arc RE = 150°

Area of sector EBR = m∠EBR/360 × π(BE²)

Area of sector EBR = 150/360 × π(9²)

Area of sector EBR = 33.75π units²

Learn more about the area of sector on:

https://brainly.com/question/22972014

#SPJ1

View image akposevictor
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.