Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
In quadrant III x-coordinates are less than 0 and y-coordinates are less than 0.
[tex]x<0 \\ y<0[/tex]
You can modify it to get other examples:
[tex]x+1<1 \\ 2y-4<-4 \\ \\ -x>0 \\ y+2<2 \\ \\ \frac{x+y}{2}<\frac{1}{2}y \\ -2y+x>x-y[/tex]
[tex]x<0 \\ y<0[/tex]
You can modify it to get other examples:
[tex]x+1<1 \\ 2y-4<-4 \\ \\ -x>0 \\ y+2<2 \\ \\ \frac{x+y}{2}<\frac{1}{2}y \\ -2y+x>x-y[/tex]
If all solutions are points in Quadrant-3, then the x-coordinates
and y-coordinates of all those points are all negative.
I believe the only possible system of liner inequalities whose
solutions have those characteristics is . . .
x < 0
y < 0 .
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.