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Given: ABCD is a parallelogram GEC ∠GEC≅∠HFA and AE ≅ FC .
Prove: △GEC≅△HFA.


Given ABCD Is A Parallelogram GEC GECHFA And AE FC Prove GECHFA class=

Sagot :

Answer:

Step-by-step explanation:

3) Congruent segments added to congruent segments form congruent segments

4) [tex]\overline{AD} \parallel \overline{BC}[/tex] (opposite sides of a parallelogram are parallel)

5) [tex]\angle FAH \cong \angle GCE[/tex] (if 2 parallel lines are cut by a transversal, the alternate interior angles are congruent)

6) [tex]\triangle GEC \cong \triangle HFA[/tex] (ASA)

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