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The average number of subscribers to an online magazine each year from 2010 to 2015 is given in the table below.

\begin{tabular}{|c|c|}
\hline Number of Years Since 2010 & Avg. Number of Subscribers \\
\hline 0 & 320,000 \\
\hline 1 & 384,000 \\
\hline 2 & 460,800 \\
\hline 3 & 552,960 \\
\hline 4 & 663,552 \\
\hline 5 & 769,262 \\
\hline
\end{tabular}

The percent increase in the average number of subscribers each year since 2010 was [tex]$\square$[/tex] \%.


Sagot :

To determine the percent increase in the average number of subscribers each year from 2010 to 2015, follow these steps:

1. Calculate the total percent increase in subscribers from year 0 (2010) to year 5 (2015).
- Initial number of subscribers in year 0 (2010) = 320,000
- Number of subscribers in year 5 (2015) = 769,262
- Total percent increase = [tex]\[\left(\frac{769,262 - 320,000}{320,000}\right) \times 100\][/tex]

2. Use the total percent increase to find the average annual percent increase over the 5 years.
- Total percent increase = 140.394375%
- Number of years = 5
- Annual percent increase = [tex]\[\frac{140.394375}{5}\][/tex]

The annual percent increase in the average number of subscribers each year since 2010 was 28.078875%.

So, the percent increase in the average number of subscribers each year since 2010 was [tex]\( \boxed{28.078875} \)[/tex]%.