Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

If A+B= 90°, then
[tex] \frac{\tan A \tan B + \tan A \cot B}{ \sin A \sec B } - \frac{{ \sin}^{2} B}{ \cos^{2} A} \: \text{is equal to }[/tex]
​

Sagot :

ridhishakya2

Answer:

A + B = 90° => A = 90 - B

So Tan A = Cot (90 - A) = Cot B

So Tan B = Cot (90 - B) = Cot A

SecB = Cosec (90 -B) = Cosec A

CosA = Sin (90 -A) = Sin B

View image ridhishakya2

The value of the angle given regarding the tangent will be tan²A.

How to explain the angle?

From the information, TanA TanB + TanACot B/SinA SecB - Sin²B/Cos²A

= TanA CotA + TanATanA/AinA CosecA - Sin²B/Sin²B

= 1 + Tan²A - 1

= Tan²A

In conclusion, the correct option is Tan²A.

Learn more about angles on:

https://brainly.com/question/25770607

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.