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Answered

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What is the equation of the line that passes through the point (6,−7) and has a slope of -3/2

Sagot :

Answer:

y = -3/2x + 2

Step-by-step explanation:

slope-line equation : y = mx + b

slope is -3/2

Let's find the y-intercept using (6, -7)

y = mx + b

-7 = -3/2(6) + b

-7 = -18/2 + b

-7 = -9 + b

+9   +9

-----------------------

2 = b

So, y = -3/2x + 2 is your equation.

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