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Find the equation of the line that is perpendicular to the line y = 2/3 x + 3 and goes through the point (0, 8).

Sagot :

kaydenkohl

Answer:

-3/2x + 8

Step-by-step explanation:

To find the slope of the perpendicular line, you take the negative reciprocal first.

2/3 -> -3/2

So far, we have y = -3/2 x + b. (since we use mx + b)

Since you asked for the line to go through (0, 8), we would usually sub in values like below, but since 8 is the y-intercept since x = 0 of the point, and we need the y-intercept, put 8 as the y-intercept.

y = -3/2 x + b

8 = -3/2(0) + b

8 = 0 + b

b = 8

So the equation that passes (0, 8) and is perpendicular to y = 2/3 x + 3 is

-3/2x + 8

Your welcome!

Kayden Kohl

8th Grade

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