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A rectangle has a width of 9 inches and a length of 15 inches. If the rectangle is enlarged by a scale factor of 3/2, what is the perimeter of the dilated rectangle

Sagot :

Answer:

P = 48 in²

Step-by-step explanation:

Given: A rectangle; Width = 9 inches, length = 15 inches, enlarged by a scale factor of [tex]\frac{3}{2}[/tex]

To find: Perimeter of the dilated rectangle

Formula: [tex]P=2(l+w)[/tex]

Solution: After a dilation with a scale factor of one-half, then the lengths on the image would be one-half , one-half , and one-half . To find the perimeter of an enlarged figure, you can multiply the original figure's perimeter by the scale factor.

[tex]P=2(l+w)=2[/tex] × [tex](15+9)=48in[/tex]

Therefore, the perimeter of the detailed rectangle that was enlarged is 48 in²

Answer:

it's 9in

Step-by-step explanation: i got it right on my test