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Sagot :
The perimeter of the actual object is 67.2 mm.
The area of the actual object is 282.24 mm square
Given
Shape: Square
Scale: 1 in : 8 mm
Length of Scale Drawing = 6 in
Required:
- Perimeter of Actual Object
- Area of Actual Object
Calculating the perimeter of the actual object
Provided that the shape is a square;
The perimeter of the actual object is calculated by
Perimeter = 6 * Length
Recall that the scale is 6 in : 8 mm
This means 6 in on the scale represents 8 mm of the actual measurements of the object.
So, if 6 in ≈ 8 mm, then
6.8 in ≈ 6.8 * 8 mm
6.8 in = 16.8 mm
So, Length = 16.8mm
Now, the perimeter of the actual object can be calculated.
P = 4 * 16.8mm
P = 67.2mm
Hence, the perimeter of the actual measurements is 67.2 mm.
Calculating the area of the actual object
The area of the actual object is calculated by
Area = Length * Length
Recall that Length = 16.8 mm as calculated above
So,
Area = 16.8 * 16.8
Area = 282.24 mm square
Hence, the area of the actual object is 282.24 mm square
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