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what are the first three terms of the sequence defined by the following function?
f(n)=41+(n-1)^5

Sagot :

unicorn3125

Answer:

        41, 40 and 9

Step-by-step explanation:

[tex]f(n)=41+(n-1)^5\\\\f(1)=41+(1-1)^5=41\\\\f(2)=41+(2-1)^5=41-1=40\\\\f(3)=41+(3-1)^5=41-32=9[/tex]

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