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2. The combustion of octane is -47.5 kJ/g.
a. Write the reaction for the combustion of octane.
b. What is the value of the enthalpy of combustion for octane per mole?
c. If the enthalpy of combustion was written with the reaction, what value would be
used?

2 The Combustion Of Octane Is 475 KJg A Write The Reaction For The Combustion Of Octane B What Is The Value Of The Enthalpy Of Combustion For Octane Per Mole C class=

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The enthalpy of combustion per mole is -5397.7 kJ/mol.

What is combustion?

The term combustion refers to a reaction in which  a substance is burnt in oxygen. Now we know that octane is a hydrocarbon and its combustion follows the general equation for the combustion of hydrocarbons.

[tex]2C_{8}H_{18} (g) + 25O_{2} (g)---- > 16CO_{2} (g) + 18H_{2} O(g)[/tex]

Given that the number of moles in one gram of octane is obtained from;

1g/114 g/mol = 0.0088 moles

If the burning of 0.0088 moles of octane produces  -47.5 kJ

Burning of 1 mole of octane would produce  1 mole * -47.5 kJ/0.0088 moles

= -5397.7 kJ/mol

We can now write is as;

[tex]2C_{8}H_{18} (g) + 25O_{2} (g)---- > 16CO_{2} (g) + 18H_{2} O(g)[/tex] ΔH = -5397.7 kJ/mol

Learn more about combustion:https://brainly.com/question/15117038

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