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At 45.0 C and a pressure of 9.9 kPa a sample of gas has a volume of 1.033 L. If the pressure is increased to 1245 kPa what will the new volume be?

Sagot :

Answer:

The new volume will be 8.2 x 10⁻³ L or 0.0082 L.

Explanation:

Since our temperature remains constant, apply Boyle's Law:

P₁V₁ = P₂V₂

Plug in the initial pressure and volume on the left side, and the new pressure on the right:

9.9(1.033) = 1245(V₂)

V₂ = (9.9(1.033)) / 1245

V₂ = 8.2 x 10⁻³ L or 0.0082 L

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