Answer:
(-2 , 2)
Step-by-step explanation:
y=x+4
y=-2x-2
x+4=-2x-2
3x=-6
x=-2
y=2
graph attached
[tex]\large\boxed{\boxed{\pink{\bf \leadsto (-2,2) \ is \ the \ solution \ of \ the \ given \ linear \ equations .}}}[/tex]
Given to equations to us are ,
[tex]\qquad \red{\bullet} \: y = x + 4 \\\\\qquad \red{\bullet} \: y = -2x - 2 [/tex]
And we need to find the solution using graphical method.
So , after plotting the graph of both equations the point where both lines intersect will be the solution of the graph.
And , for plotting we need at least two points .
For equation (1) :-
[tex]\implies y = x + 4 [/tex]
When x = (-4) .
[tex]\implies y = -4+4\\\\\bf\implies y = 0 [/tex]
When x = (-3)
[tex]\implies y = -3+4\\\\\bf\implies y = -1 [/tex]
[tex]\large\boxed{\begin{tabular}{|c|c|c|} \cline{1-3} \bf x & (-4) & (-3) \\\cline{1-3} \bf y & 0 & 1 \\\cline{1-3}\end{tabular}}[/tex]
For equation 2 :-
[tex]\implies y = -2x - 2 [/tex]
When x = (-1) .
[tex]\implies y = -2(-1)-2\\\\\bf\implies y = 0 [/tex]
When x = (0)
[tex]\implies y = 0-2\\\\\bf\implies y = -2 [/tex]
[tex]\large\boxed{\begin{tabular}{|c|c|c|} \cline{1-3} \bf x & (-1) & 0 \\\cline{1-3} \bf y & 0 & -2 \\\cline{1-3}\end{tabular}}[/tex]
Now , let's plot their graphs. Graph is in attachment. Hence on plotting the graph we see that both the lines Intersect on (-2,2) . Hence x = -2 and y = 2 is the solution of the given linear equation.
