Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

6x-2y=33
4x+3y=9 What would x and y be?

Sagot :

mariamikayla
[tex]6x-2y=33 \\\\ 6x=33+2y \\\\ \boxed{x=\frac{2y+33}{6}} \\\\ 4x+3y=9 \\\\ 4*\frac{2y+33}{6}+3y=9 \\\\ 2*\frac{2y+33}{3}+3y^{(3}=9^{(3} \\\\ 2(2y+33)+9y=27 \\\\ 4y+66+9y=27 \\\\ 13y=27-66 \\\\ 13y=- 39 \\\\ \boxed{y=-\frac{39}{13}=-3} \\\\ x=\frac{2*(-3)+33}{6} \\\\ x=\frac{-6+33}{6} \\\\ x=\frac{27}{6} \\\\ \boxed{x=\frac{9}{2}}[/tex]
Johnweshas
To find the variables of the equations, use systems of equations.

First get rid of one variable. Let's get rid of the y by multiplyin both equations nad then adding them.
[tex](6x-2y=33)3[/tex]
[tex](4x+3y=9)2[/tex]

[tex]18x-6y=99[/tex]
[tex]8x+6y=18[/tex]
[tex]26x=117[/tex]

Solve for x:
[tex] \frac{26x}{26} = \frac{117}{26} [/tex]
[tex]x=4.5[/tex]

Now you have x! Plug x into one quation and solve for y:
[tex]6(4.5)-2y=33[/tex]
[tex]27-2y=33[/tex]
[tex] \frac{-2y}{-2} = \frac{6}{-2} [/tex]
[tex]y=-3[/tex]

[tex]x=4.5, y=-3[/tex]
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.