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Find the area of a triangle that has a base of 5 in and a height of 3 3/4 in

Sagot :

Ryan2
Remember:

[tex]3\frac{3}{4}=\frac{15}{4}[/tex]

Area of a triangle

[tex]A=\frac{1}{2}.b.h\\ \\ A=\frac{1}{2}*5*\frac{15}{4}=\frac{75}{8}=9\frac{3}{8} \ in^2[/tex]
MathG33k
[tex]Area= \frac{bh}{2} \\ \\ 5*3.75=18.75 \\ \\ \frac{18.75}{2} = 9.375 \\\\\boxed{9.375}[/tex]
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