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Sagot :
[tex]g-green\ marbles\\r-red\ marbles\\b-blue\ marbles\\g+r+b=33\\\\4g-red\ marbles\\\frac{1}{2}g-blue\ marbles\\\\g+4g+\frac{1}{2}g=33\\\\5\frac{1}{2}g=33\\\\\frac{11}{2}g=33\ \ \ \ /\cdot\frac{2}{11}\\\\g=3\\\\Answer:b=\frac{1}{2}g\to b=\frac{1}{2}\cdot6=3[/tex]
Answer:
The number of blue marbles be 3.
Step-by-step explanation:
As given
A drawer has some red ,green and blue marbles.
There are 33 marbles .
there are 4 times as many red marbles as green marbles.
Let us assume that the number of green marbles be g .
Than Red marbles = 4g
There are half as many blue marbles as green marbles.
Than
[tex]Number\ of\ blue\ marbles =\frac {Number\ of\ green\ marbles}{2}[/tex]
[tex]Number\ of\ blue\ marbles =\frac{g}{2}[/tex]
Than the equation becomes
[tex]g + 4g + \frac{g}{2} = 33[/tex]
Than simplify the above
[tex]2g + 8g + g = 33\times 2[/tex]
[tex]11g = 66[/tex]
[tex]g= \frac{66}{11}[/tex]
g = 6
[tex]Number\ of\ blue\ marbles =\frac{6}{2}[/tex]
Number of blue marbles = 3
Therefore the number of blue marbles be 3 .
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