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Solve the given equation on the domain [0,2π]: 2sinx-sqrt(2)=0

sqrt=squareroot

Sagot :

AL2006
2 sin(x) - √2 = 0

2 sin(x) = √2

sin(x) = (1/2) √2

x = sin⁻¹ ( 1/2 √2 ) = 45° and 135° .
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