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how do I solve (3+i)(3-i)

Sagot :

kate200468
[tex] (3+i)(3-i)=3(3-i)+i(3-i)=9-3i+3i-i^2=9-(-1)=\\\\=9+1=10[/tex]
kayt91
(3+I)(3-1)
-i^2+9=0
-I^2=-9
I^2=9
i= + or - 3
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