Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
We are given two products and we need to subtract one from the other. First, let's compute each of these products step-by-step.
### Step 1: Compute the product of terms [tex]\(\left(\frac{4}{3} l^2 m n\right), \left(-5 l m n^2\right)\)[/tex], and [tex]\(\left(\frac{1}{3} l^2 m n\right)\)[/tex]
1. Multiply [tex]\(\left(\frac{4}{3} l^2 m n\right)\)[/tex] and [tex]\(\left(-5 l m n^2\right)\)[/tex]:
[tex]\[ \left(\frac{4}{3} l^2 m n\right) \cdot \left(-5 l m n^2\right) = \left(\frac{4}{3} \cdot -5\right) \cdot l^2 \cdot l \cdot m \cdot m \cdot n \cdot n^2 \][/tex]
[tex]\[ = \left(-\frac{20}{3}\right) \cdot l^3 \cdot m^2 \cdot n^3 \][/tex]
2. Now, multiply the result by [tex]\(\left(\frac{1}{3} l^2 m n\right)\)[/tex]:
[tex]\[ \left(-\frac{20}{3} l^3 m^2 n^3\right) \cdot \left(\frac{1}{3} l^2 m n\right) = \left(-\frac{20}{3} \cdot \frac{1}{3}\right) \cdot l^3 \cdot l^2 \cdot m^2 \cdot m \cdot n^3 \cdot n \][/tex]
[tex]\[ = \left(-\frac{20}{9}\right) \cdot l^{5} \cdot m^{3} \cdot n^{4} \][/tex]
### Step 2: Compute the product of terms [tex]\(\left(\frac{7}{3} l^3 m n^2\right)\)[/tex] and [tex]\(\left(\frac{2}{3} l^2 m^2 n^2\right)\)[/tex]
1. Multiply the terms directly:
[tex]\[ \left(\frac{7}{3} l^3 m n^2\right) \cdot \left(\frac{2}{3} l^2 m^2 n^2\right) = \left(\frac{7}{3} \cdot \frac{2}{3}\right) \cdot l^3 \cdot l^2 \cdot m \cdot m^2 \cdot n^2 \cdot n^2 \][/tex]
[tex]\[ = \left(\frac{14}{9}\right) \cdot l^5 \cdot m^3 \cdot n^4 \][/tex]
### Step 3: Subtract the second product from the first product
[tex]\[ \left(-\frac{20}{9} l^{5} m^{3} n^{4}\right) - \left(\frac{14}{9} l^{5} m^{3} n^{4}\right) = \frac{-20 - 14}{9} l^{5} m^{3} n^{4} = \frac{-34}{9} l^{5} m^{3} n^{4} \][/tex]
Thus, the final result after subtracting the second product from the first is:
[tex]\[ \boxed{-\frac{34}{9} l^5 m^3 n^4} \][/tex]
### Step 1: Compute the product of terms [tex]\(\left(\frac{4}{3} l^2 m n\right), \left(-5 l m n^2\right)\)[/tex], and [tex]\(\left(\frac{1}{3} l^2 m n\right)\)[/tex]
1. Multiply [tex]\(\left(\frac{4}{3} l^2 m n\right)\)[/tex] and [tex]\(\left(-5 l m n^2\right)\)[/tex]:
[tex]\[ \left(\frac{4}{3} l^2 m n\right) \cdot \left(-5 l m n^2\right) = \left(\frac{4}{3} \cdot -5\right) \cdot l^2 \cdot l \cdot m \cdot m \cdot n \cdot n^2 \][/tex]
[tex]\[ = \left(-\frac{20}{3}\right) \cdot l^3 \cdot m^2 \cdot n^3 \][/tex]
2. Now, multiply the result by [tex]\(\left(\frac{1}{3} l^2 m n\right)\)[/tex]:
[tex]\[ \left(-\frac{20}{3} l^3 m^2 n^3\right) \cdot \left(\frac{1}{3} l^2 m n\right) = \left(-\frac{20}{3} \cdot \frac{1}{3}\right) \cdot l^3 \cdot l^2 \cdot m^2 \cdot m \cdot n^3 \cdot n \][/tex]
[tex]\[ = \left(-\frac{20}{9}\right) \cdot l^{5} \cdot m^{3} \cdot n^{4} \][/tex]
### Step 2: Compute the product of terms [tex]\(\left(\frac{7}{3} l^3 m n^2\right)\)[/tex] and [tex]\(\left(\frac{2}{3} l^2 m^2 n^2\right)\)[/tex]
1. Multiply the terms directly:
[tex]\[ \left(\frac{7}{3} l^3 m n^2\right) \cdot \left(\frac{2}{3} l^2 m^2 n^2\right) = \left(\frac{7}{3} \cdot \frac{2}{3}\right) \cdot l^3 \cdot l^2 \cdot m \cdot m^2 \cdot n^2 \cdot n^2 \][/tex]
[tex]\[ = \left(\frac{14}{9}\right) \cdot l^5 \cdot m^3 \cdot n^4 \][/tex]
### Step 3: Subtract the second product from the first product
[tex]\[ \left(-\frac{20}{9} l^{5} m^{3} n^{4}\right) - \left(\frac{14}{9} l^{5} m^{3} n^{4}\right) = \frac{-20 - 14}{9} l^{5} m^{3} n^{4} = \frac{-34}{9} l^{5} m^{3} n^{4} \][/tex]
Thus, the final result after subtracting the second product from the first is:
[tex]\[ \boxed{-\frac{34}{9} l^5 m^3 n^4} \][/tex]
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.