Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Consider the following reversible reaction:

[tex]\[ CO(g) + 2H_2(g) \longleftrightarrow CH_3OH(g) \][/tex]

What is the equilibrium constant expression for the given system?

A. [tex]\[ Keq = \frac{[CO][H_2]^2}{[CH_3OH]} \][/tex]

B. [tex]\[ Keq = \frac{[CH_3OH]}{[CO][H_2]^2} \][/tex]

C. [tex]\[ Keq = \frac{[CO][H_2]}{[CH_3OH]} \][/tex]

D. [tex]\[ Keq = \frac{[CH_3OH]}{[CO][H_2]} \][/tex]

Sagot :

GinnyAnswer
Certainly! Let's consider the reversible reaction:

[tex]\[ CO (g) + 2 H_2 (g) \rightleftharpoons CH_3OH (g) \][/tex]

To determine the equilibrium constant expression ([tex]\( K_{\text{eq}} \)[/tex]), we need to use the general formula for [tex]\( K_{\text{eq}} \)[/tex] of a reaction of the form:

[tex]\[ aA + bB \rightleftharpoons cC + dD \][/tex]

The equilibrium constant is given by:

[tex]\[ K_{\text{eq}} = \frac{[C]^c [D]^d}{[A]^a [B]^b} \][/tex]

For our specific reaction:

[tex]\[ CO (g) + 2 H_2 (g) \rightleftharpoons CH_3OH (g) \][/tex]

- [tex]\( A \)[/tex] = [tex]\( CO \)[/tex] with a coefficient of 1
- [tex]\( B \)[/tex] = [tex]\( H_2 \)[/tex] with a coefficient of 2
- [tex]\( C \)[/tex] = [tex]\( CH_3OH \)[/tex] with a coefficient of 1
- There are no other products.

According to the formula, the equilibrium constant expression will be:

[tex]\[ K_{\text{eq}} = \frac{[CH_3OH]^1}{[CO]^1[H_2]^2} \][/tex]

Simplified, it appears as:

[tex]\[ K_{\text{eq}} = \frac{[CH_3OH]}{[CO][H_2]^2} \][/tex]

Thus, the correct expression for the equilibrium constant for the given reaction is:

[tex]\[ K_{\text{eq}} = \frac{[CH_3OH]}{[CO][H_2]^2} \][/tex]
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.