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Experimental yield: 2.86 g

You already saw that 1.00 g of Al should yield 3.53 g of copper for the reaction below:
[tex]\[ 3 \text{CuCl}_2(aq) + 2 \text{Al}(s) \rightarrow 2 \text{AlCl}_3(aq) + 3 \text{Cu}(s) \][/tex]

However, impurities and errors can occur easily. Suppose that only 2.86 g of copper is produced.

What is the percent yield of the reaction? [tex]$\square$[/tex]


Sagot :

To determine the percent yield of the reaction, follow these step-by-step instructions:

1. Understand the given data:
- Theoretical yield: This is the maximum amount of product that can be produced assuming everything goes perfectly and without any losses. In this case, the theoretical yield of copper is 3.53 grams.
- Actual yield: This is the amount of product that was actually obtained from the experiment. Here, the actual yield of copper is 2.86 grams.

2. Write down the formula for percent yield:
[tex]\[ \text{Percent yield} = \left( \frac{\text{Actual yield}}{\text{Theoretical yield}} \right) \times 100 \][/tex]

3. Substitute the values into the formula:
[tex]\[ \text{Percent yield} = \left( \frac{2.86 \, \text{g}}{3.53 \, \text{g}} \right) \times 100 \][/tex]

4. Calculate the fraction:
[tex]\[ \frac{2.86}{3.53} \approx 0.8101983002832861 \][/tex]

5. Convert the fraction to a percentage:
[tex]\[ 0.8101983002832861 \times 100 \approx 81.01983002832861 \][/tex]

6. Round to a suitable number of decimal places, if necessary:
Typically, percent yields are reported to two decimal places, so we can round it to 81.02.

Therefore, the percent yield of the reaction is approximately [tex]\( \boxed{81.02} \% \)[/tex].