Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Solve for [tex]x[/tex].

[tex]\[ 3x = 6x - 2 \][/tex]

---

Rewrite the following expression:

[tex]\[ \operatorname{Tan}\left(a + 5^{\circ}\right) = \sqrt{2 \sin 30^{\circ} + \sec^2 45^{\circ}} \][/tex]

---

Read the lines from "The Tide Rises, The Tide Falls":

"Darkness settles on roofs and walls,
But the sea, the sea in darkness calls;"

The imagery in these lines evokes a sense of:
A. laziness
B. fear
C. mystery
D. despair


Sagot :

Sure, let's solve the given expression step-by-step:

We need to evaluate [tex]\(\operatorname{Tan}\left(a+5^{\circ}\right) \)[/tex] given that:

[tex]\[ \operatorname{Tan}\left(a+5^{\circ}\right)=\sqrt{2 \sin 30^{\circ}+\sec^2 45^{\circ}} \][/tex]

1. Calculate [tex]\(\sin 30^\circ\)[/tex]
[tex]\[ \sin 30^\circ = \frac{1}{2} = 0.5 \][/tex]

2. Calculate [tex]\(\sec 45^\circ\)[/tex]
The secant function is the reciprocal of the cosine function. Therefore:
[tex]\[ \sec 45^\circ = \frac{1}{\cos 45^\circ} = \frac{1}{\frac{\sqrt{2}}{2}} = \sqrt{2} \][/tex]

3. Square [tex]\(\sec 45^\circ\)[/tex]
[tex]\[ \sec^2 45^\circ = (\sqrt{2})^2 = 2 \][/tex]

4. Substitute [tex]\(\sin 30^\circ\)[/tex] and [tex]\(\sec^2 45^\circ\)[/tex] into the expression inside the square root
[tex]\[ 2 \sin 30^\circ + \sec^2 45^\circ = 2 \times 0.5 + 2 = 1 + 2 = 3 \][/tex]

5. Take the square root of the expression
[tex]\[ \sqrt{3} \approx 1.73205 \][/tex]

6. Evaluate [tex]\(\operatorname{Tan}\left(a+5^{\circ}\right)\)[/tex] where the value of [tex]\(a\)[/tex] is 5
We need to find the tan of the angle [tex]\(10^\circ\)[/tex] (since [tex]\(a + 5 = 5 + 5 = 10\)[/tex]):
[tex]\[ \tan(10^\circ) \approx 0.17632698070846498 \][/tex]

So, the step-by-step solution shows that:

[tex]\[ \operatorname{Tan}\left(a+5^{\circ}\right) \approx 0.17632698070846498 \][/tex]

Therefore:

[tex]\[ \operatorname{Tan}\left(10^\circ\right) = \sqrt{2 \sin 30^{\circ} + \sec^2 45^{\circ}} \approx 0.17632698070846498 \][/tex]
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.