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Drag each quantity to the correct location on the table.
Complete the table of bond energies and bond lengths.

[tex]$125 \text{ pm} \quad 145 \text{ pm} \quad 167 \text{ kJ/mol} \quad 942 \text{ kJ/mol} \quad 110 \text{ pm} \quad 418 \text{ kJ/mol}$[/tex]

\begin{tabular}{|l|l|l|}
\hline
& Bond Energy & Bond Length \\
\hline
[tex]$N - N$[/tex] & & \\
\hline
[tex]$N = N$[/tex] & & \\
\hline
[tex]$N \equiv N$[/tex] & & \\
\hline
\end{tabular}

Sagot :

GinnyAnswer
Certainly! Let's fill in the table with the given quantities of bond energies and bond lengths for each type of nitrogen bond:

- Single Bond (N - N):
- Bond Energy: 167 kJ/mol
- Bond Length: 145 pm

- Double Bond (N = N):
- Bond Energy: 418 kJ/mol
- Bond Length: 125 pm

- Triple Bond (N ≡ N):
- Bond Energy: 942 kJ/mol
- Bond Length: 110 pm

So, the completed table will look like this:

[tex]\[ \begin{array}{|l|l|l|} \hline & \text{Bond Energy} & \text{Bond Length} \\ \hline \text{N - N} & 167 \ \text{kJ/mol} & 145 \ \text{pm} \\ \hline \text{N = N} & 418 \ \text{kJ/mol} & 125 \ \text{pm} \\ \hline \text{N} \equiv \text{N} & 942 \ \text{kJ/mol} & 110 \ \text{pm} \\ \hline \end{array} \][/tex]
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