Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Ask your questions and receive precise answers from experienced professionals across different disciplines. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
To balance the molecular equation for the reaction between the weak base sodium hypochlorite ([tex]\(\text{NaClO (aq)}\)[/tex]) and the strong acid sulfuric acid ([tex]\(\text{H}_2\text{SO}_4\text{(aq)}\)[/tex]), let's follow these steps:
1. List the reacting compounds and their respective elements:
- [tex]\(\text{NaClO}\)[/tex]
- Sodium (Na): 1
- Chlorine (Cl): 1
- Oxygen (O): 1
- [tex]\(\text{H}_2\text{SO}_4\)[/tex]
- Hydrogen (H): 2
- Sulfur (S): 1
- Oxygen (O): 4
2. Identify the products and balance each element:
- Products: [tex]\(\text{HClO} \text{ (aq)}\)[/tex] and [tex]\(\text{NaHSO}_4 \text{ (aq)}\)[/tex]
- [tex]\(\text{HClO}\)[/tex]
- Hydrogen (H): 1
- Chlorine (Cl): 1
- Oxygen (O): 1
- [tex]\(\text{NaHSO}_4\)[/tex]
- Sodium (Na): 1
- Hydrogen (H): 1
- Sulfur (S): 1
- Oxygen (O): 4
3. Ensure both sides of the reaction have equal numbers of atoms for each element:
- Left side (Reactants):
- Sodium (Na): 1 from [tex]\(\text{NaClO}\)[/tex]
- Chlorine (Cl): 1 from [tex]\(\text{NaClO}\)[/tex]
- Oxygen (O): 1 from [tex]\(\text{NaClO}\)[/tex] + 4 from [tex]\(\text{H}_2\text{SO}_4\)[/tex] = 5
- Hydrogen (H): 2 from [tex]\(\text{H}_2\text{SO}_4\)[/tex]
- Sulfur (S): 1 from [tex]\(\text{H}_2\text{SO}_4\)[/tex]
- Right side (Products):
- Sodium (Na): 1 from [tex]\(\text{NaHSO}_4\)[/tex]
- Chlorine (Cl): 1 from [tex]\(\text{HClO}\)[/tex]
- Oxygen (O): 1 from [tex]\(\text{HClO}\)[/tex] + 4 from [tex]\(\text{NaHSO}_4\)[/tex] = 5
- Hydrogen (H): 1 from [tex]\(\text{HClO}\)[/tex] + 1 from [tex]\(\text{NaHSO}_4\)[/tex] = 2
- Sulfur (S): 1 from [tex]\(\text{NaHSO}_4\)[/tex]
Since each element has the same number of atoms on both sides of the reaction equation, the equation is balanced.
4. Write the balanced equation:
[tex]\[ \text{NaClO (aq)} + \text{H}_2\text{SO}_4\text{(aq)} \rightarrow \text{HClO (aq)} + \text{NaHSO}_4\text{(aq)} \][/tex]
Thus, the balanced molecular reaction for the given weak base and strong acid is:
[tex]\[ \text{NaClO (aq)} + \text{H}_2\text{SO}_4\text{(aq)} \rightarrow \text{HClO (aq)} + \text{NaHSO}_4\text{(aq)} \][/tex]
1. List the reacting compounds and their respective elements:
- [tex]\(\text{NaClO}\)[/tex]
- Sodium (Na): 1
- Chlorine (Cl): 1
- Oxygen (O): 1
- [tex]\(\text{H}_2\text{SO}_4\)[/tex]
- Hydrogen (H): 2
- Sulfur (S): 1
- Oxygen (O): 4
2. Identify the products and balance each element:
- Products: [tex]\(\text{HClO} \text{ (aq)}\)[/tex] and [tex]\(\text{NaHSO}_4 \text{ (aq)}\)[/tex]
- [tex]\(\text{HClO}\)[/tex]
- Hydrogen (H): 1
- Chlorine (Cl): 1
- Oxygen (O): 1
- [tex]\(\text{NaHSO}_4\)[/tex]
- Sodium (Na): 1
- Hydrogen (H): 1
- Sulfur (S): 1
- Oxygen (O): 4
3. Ensure both sides of the reaction have equal numbers of atoms for each element:
- Left side (Reactants):
- Sodium (Na): 1 from [tex]\(\text{NaClO}\)[/tex]
- Chlorine (Cl): 1 from [tex]\(\text{NaClO}\)[/tex]
- Oxygen (O): 1 from [tex]\(\text{NaClO}\)[/tex] + 4 from [tex]\(\text{H}_2\text{SO}_4\)[/tex] = 5
- Hydrogen (H): 2 from [tex]\(\text{H}_2\text{SO}_4\)[/tex]
- Sulfur (S): 1 from [tex]\(\text{H}_2\text{SO}_4\)[/tex]
- Right side (Products):
- Sodium (Na): 1 from [tex]\(\text{NaHSO}_4\)[/tex]
- Chlorine (Cl): 1 from [tex]\(\text{HClO}\)[/tex]
- Oxygen (O): 1 from [tex]\(\text{HClO}\)[/tex] + 4 from [tex]\(\text{NaHSO}_4\)[/tex] = 5
- Hydrogen (H): 1 from [tex]\(\text{HClO}\)[/tex] + 1 from [tex]\(\text{NaHSO}_4\)[/tex] = 2
- Sulfur (S): 1 from [tex]\(\text{NaHSO}_4\)[/tex]
Since each element has the same number of atoms on both sides of the reaction equation, the equation is balanced.
4. Write the balanced equation:
[tex]\[ \text{NaClO (aq)} + \text{H}_2\text{SO}_4\text{(aq)} \rightarrow \text{HClO (aq)} + \text{NaHSO}_4\text{(aq)} \][/tex]
Thus, the balanced molecular reaction for the given weak base and strong acid is:
[tex]\[ \text{NaClO (aq)} + \text{H}_2\text{SO}_4\text{(aq)} \rightarrow \text{HClO (aq)} + \text{NaHSO}_4\text{(aq)} \][/tex]
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.