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Solve for [tex]$b_1$[/tex]:
[tex]\[ a = \frac{b_2 - b_1}{h} \][/tex]

A. [tex]$b_1 = -h a - b_2$[/tex]

B. [tex]$b_1 = h a - b_2$[/tex]

C. [tex][tex]$b_1 = h a + b_2$[/tex][/tex]

D. [tex]$b_1 = -h a + b_2$[/tex]


Sagot :

Let's solve the equation [tex]\(a = \frac{b_2 - b_1}{h}\)[/tex] for [tex]\(b_1\)[/tex].

Given equation:
[tex]\[ a = \frac{b_2 - b_1}{h} \][/tex]

Step 1: Eliminate the denominator on the right-hand side by multiplying both sides by [tex]\(h\)[/tex]:
[tex]\[ a \cdot h = \frac{b_2 - b_1}{h} \cdot h \][/tex]
[tex]\[ a h = b_2 - b_1 \][/tex]

Step 2: Isolate [tex]\(-b_1\)[/tex] by subtracting [tex]\(b_2\)[/tex] from both sides:
[tex]\[ a h - b_2 = b_2 - b_1 - b_2 \][/tex]
[tex]\[ a h - b_2 = -b_1 \][/tex]

Step 3: Multiply both sides of the equation by [tex]\(-1\)[/tex] to solve for [tex]\(b_1\)[/tex]:
[tex]\[ -b_1 \cdot (-1) = (a h - b_2) \cdot (-1) \][/tex]
[tex]\[ b_1 = -a h + b_2 \][/tex]

Therefore, the correct answer is:
(D) [tex]\(\boxed{b_1 = -h a + b_2}\)[/tex]