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What is the principal square root of [tex]$81$[/tex]?

Sagot :

GinnyAnswer
To find the principal square root of [tex]\( 81 \)[/tex], you can follow these steps:

1. Recall the definition of the principal square root. The principal square root of a non-negative number [tex]\( x \)[/tex] is the non-negative number [tex]\( y \)[/tex] such that [tex]\( y^2 = x \)[/tex].

2. Identify the number whose principal square root you need to find. In this case, it is [tex]\( 81 \)[/tex].

3. Determine a number [tex]\( y \)[/tex] such that [tex]\( y^2 = 81 \)[/tex].

4. Through knowledge of square numbers, recognize that [tex]\( 9^2 = 81 \)[/tex].

5. Therefore, [tex]\( 9 \)[/tex] is the principal square root of [tex]\( 81 \)[/tex].

So, the principal square root of [tex]\( 81 \)[/tex] is [tex]\( 9.0 \)[/tex].
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