Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
To find the coordinates of [tex]\( K' \)[/tex] after translating point [tex]\( K \)[/tex], we need to determine the translation vector that maps point [tex]\( J \)[/tex] to [tex]\( J' \)[/tex]. Here are the coordinates given:
- [tex]\( J(2, 4) \)[/tex]
- [tex]\( J'(3, 3) \)[/tex]
- [tex]\( K(3, 1) \)[/tex]
Step-by-Step Solution:
1. Determine the translation vector:
- The translation vector is calculated by finding the difference in the x-coordinates and y-coordinates of [tex]\( J \)[/tex] and [tex]\( J' \)[/tex]:
[tex]\[ \text{Translation vector} = (J'_x - J_x, J'_y - J_y) \][/tex]
- Substitute the given coordinates of [tex]\( J \)[/tex] and [tex]\( J' \)[/tex]:
[tex]\[ \text{Translation vector} = (3 - 2, 3 - 4) = (1, -1) \][/tex]
2. Apply the translation vector to point [tex]\( K \)[/tex]:
- To find the coordinates of [tex]\( K' \)[/tex], we add the components of the translation vector to the coordinates of [tex]\( K \)[/tex]:
[tex]\[ K'_x = K_x + 1 \][/tex]
[tex]\[ K'_y = K_y - 1 \][/tex]
- Substitute the given coordinates of [tex]\( K \)[/tex]:
[tex]\[ K'_x = 3 + 1 = 4 \][/tex]
[tex]\[ K'_y = 1 - 1 = 0 \][/tex]
3. Conclusion:
- Therefore, the coordinates of [tex]\( K' \)[/tex] are [tex]\((4, 0)\)[/tex].
So, the correct coordinates of [tex]\( K' \)[/tex] are [tex]\( \boxed{(4, 0)} \)[/tex].
- [tex]\( J(2, 4) \)[/tex]
- [tex]\( J'(3, 3) \)[/tex]
- [tex]\( K(3, 1) \)[/tex]
Step-by-Step Solution:
1. Determine the translation vector:
- The translation vector is calculated by finding the difference in the x-coordinates and y-coordinates of [tex]\( J \)[/tex] and [tex]\( J' \)[/tex]:
[tex]\[ \text{Translation vector} = (J'_x - J_x, J'_y - J_y) \][/tex]
- Substitute the given coordinates of [tex]\( J \)[/tex] and [tex]\( J' \)[/tex]:
[tex]\[ \text{Translation vector} = (3 - 2, 3 - 4) = (1, -1) \][/tex]
2. Apply the translation vector to point [tex]\( K \)[/tex]:
- To find the coordinates of [tex]\( K' \)[/tex], we add the components of the translation vector to the coordinates of [tex]\( K \)[/tex]:
[tex]\[ K'_x = K_x + 1 \][/tex]
[tex]\[ K'_y = K_y - 1 \][/tex]
- Substitute the given coordinates of [tex]\( K \)[/tex]:
[tex]\[ K'_x = 3 + 1 = 4 \][/tex]
[tex]\[ K'_y = 1 - 1 = 0 \][/tex]
3. Conclusion:
- Therefore, the coordinates of [tex]\( K' \)[/tex] are [tex]\((4, 0)\)[/tex].
So, the correct coordinates of [tex]\( K' \)[/tex] are [tex]\( \boxed{(4, 0)} \)[/tex].
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.