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Find [tex]\(\theta\)[/tex], if [tex]\(0^{\circ} \ \textless \ \theta \ \textless \ 360^{\circ}\)[/tex] and [tex]\(\sin \theta = -\frac{\sqrt{3}}{2}\)[/tex] and [tex]\(\theta\)[/tex] is in QIV.

[tex]\(\theta = \boxed{\text{degrees}}\)[/tex]


Sagot :

To find [tex]\(\theta\)[/tex] when [tex]\(0^\circ < \theta < 360^\circ\)[/tex] and [tex]\(\sin \theta = -\frac{\sqrt{3}}{2}\)[/tex] with [tex]\(\theta\)[/tex] in the fourth quadrant (QIV), follow these steps:

1. Determine the reference angle:
- The reference angle is the angle in the first quadrant that has the same sine value ignoring the sign. For [tex]\(\sin \theta = \frac{\sqrt{3}}{2}\)[/tex], the reference angle is [tex]\(60^\circ\)[/tex].

2. Place the angle in the correct quadrant:
- Since we know [tex]\(\sin \theta = -\frac{\sqrt{3}}{2}\)[/tex], and sine is negative in the fourth quadrant, we will use the reference angle to find [tex]\(\theta\)[/tex] in QIV.

3. Calculate the angle in the fourth quadrant:
- In the fourth quadrant, the angle can be found using [tex]\(360^\circ\)[/tex] minus the reference angle.
- Thus, [tex]\(\theta = 360^\circ - 60^\circ\)[/tex].
- So, [tex]\(\theta = 300^\circ\)[/tex].

Therefore, [tex]\(\theta = 300^\circ\)[/tex] and the reference angle is [tex]\(60^\circ\)[/tex].
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