At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
To determine the density, we start with two given quantities: total mass and volume.
1. Total Mass: The total mass given is 600 pounds.
2. Volume: The volume given is 85 cubic feet.
Density (denoted as [tex]\( \rho \)[/tex]) is calculated using the formula:
[tex]\[ \rho = \frac{\text{mass}}{\text{volume}} \][/tex]
Plugging in the given values:
[tex]\[ \rho = \frac{600 \text{ pounds}}{85 \text{ cubic feet}} \][/tex]
Performing the division:
[tex]\[ \rho = 7.06 \text{ pounds per cubic foot} \][/tex]
Given the context, the units should be adjusted. The question mentions a unit of pounds per [tex]\( 600 t^2 \)[/tex]. However, typically, the unit of density derived in this type of problem would be pounds per cubic foot.
However, based on the constraint (place the correct numeric answer in the density box):
The result is:
[tex]\[ \boxed{7.06} \quad \frac{\text{ pounds }}{600 t ^2} \][/tex]
(Note: It is understood that there is a mistake in the unit [tex]\(600 t^2\)[/tex], and it should likely be [tex]\(\frac{\text{ pounds }}{\text{ cubic feet }}\)[/tex], or this might be a hypothetical unit given in the problem.)
1. Total Mass: The total mass given is 600 pounds.
2. Volume: The volume given is 85 cubic feet.
Density (denoted as [tex]\( \rho \)[/tex]) is calculated using the formula:
[tex]\[ \rho = \frac{\text{mass}}{\text{volume}} \][/tex]
Plugging in the given values:
[tex]\[ \rho = \frac{600 \text{ pounds}}{85 \text{ cubic feet}} \][/tex]
Performing the division:
[tex]\[ \rho = 7.06 \text{ pounds per cubic foot} \][/tex]
Given the context, the units should be adjusted. The question mentions a unit of pounds per [tex]\( 600 t^2 \)[/tex]. However, typically, the unit of density derived in this type of problem would be pounds per cubic foot.
However, based on the constraint (place the correct numeric answer in the density box):
The result is:
[tex]\[ \boxed{7.06} \quad \frac{\text{ pounds }}{600 t ^2} \][/tex]
(Note: It is understood that there is a mistake in the unit [tex]\(600 t^2\)[/tex], and it should likely be [tex]\(\frac{\text{ pounds }}{\text{ cubic feet }}\)[/tex], or this might be a hypothetical unit given in the problem.)
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.