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Sagot :
To calculate the molar concentration (molarity) of the solution, we need to use the formula:
[tex]\[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \][/tex]
We are given:
- Moles of FeCl[tex]\(_2\)[/tex] = 1.775 moles
- Volume of the solution = 450 mL
First, we need to convert the volume from milliliters to liters, because molarity is expressed in moles per liter.
[tex]\[ 1 \text{ liter} = 1000 \text{ milliliters} \][/tex]
Thus,
[tex]\[ \text{Volume in liters} = \frac{450 \text{ mL}}{1000} = 0.45 \text{ liters} \][/tex]
Next, we use the formula for molarity:
[tex]\[ \text{Molarity (M)} = \frac{1.775 \text{ moles}}{0.45 \text{ liters}} \][/tex]
Dividing the moles by the volume in liters gives:
[tex]\[ \text{Molarity (M)} = 3.944444444444444 \text{ mol/L} \][/tex]
Therefore, the molar concentration of the FeCl[tex]\(_2\)[/tex] solution is approximately [tex]\( 3.944 \text{ mol/L} \)[/tex].
[tex]\[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \][/tex]
We are given:
- Moles of FeCl[tex]\(_2\)[/tex] = 1.775 moles
- Volume of the solution = 450 mL
First, we need to convert the volume from milliliters to liters, because molarity is expressed in moles per liter.
[tex]\[ 1 \text{ liter} = 1000 \text{ milliliters} \][/tex]
Thus,
[tex]\[ \text{Volume in liters} = \frac{450 \text{ mL}}{1000} = 0.45 \text{ liters} \][/tex]
Next, we use the formula for molarity:
[tex]\[ \text{Molarity (M)} = \frac{1.775 \text{ moles}}{0.45 \text{ liters}} \][/tex]
Dividing the moles by the volume in liters gives:
[tex]\[ \text{Molarity (M)} = 3.944444444444444 \text{ mol/L} \][/tex]
Therefore, the molar concentration of the FeCl[tex]\(_2\)[/tex] solution is approximately [tex]\( 3.944 \text{ mol/L} \)[/tex].
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