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The exact times, in seconds, of four sprinters from a school track meet are as follows:

\begin{tabular}{|l|l|l|l|l|}
\hline Sprinter & Sprinter A & Sprinter B & Sprinter C & Sprinter D \\
\hline Time & 132.38 & 132.31 & 132.29 & 132.25 \\
\hline
\end{tabular}

If the stopwatch used was precise only to the tenths place, which sprinter's time is different from the others?

A. Sprinter B
B. Sprinter C
C. Sprinter D
D. Sprinter A

Sagot :

GinnyAnswer
To determine which sprinter's time is different from the others when rounded to the tenths place, we will follow these steps:

1. List the exact times of each sprinter:
- Sprinter A: 132.38 seconds
- Sprinter B: 132.31 seconds
- Sprinter C: 132.29 seconds
- Sprinter D: 132.25 seconds

2. Round each time to the tenths place:
- Sprinter A: 132.38 rounds to 132.4
- Sprinter B: 132.31 rounds to 132.3
- Sprinter C: 132.29 rounds to 132.3
- Sprinter D: 132.25 rounds to 132.3

3. Identify the rounded times:
- Rounded time for Sprinter A: 132.4
- Rounded time for Sprinter B: 132.3
- Rounded time for Sprinter C: 132.3
- Rounded time for Sprinter D: 132.3

4. Compare the rounded times to see which one is unique:
- Sprinter B, Sprinter C, and Sprinter D all have the rounded time of 132.3.
- Sprinter A has a unique rounded time of 132.4.

Therefore, Sprinter A's time is different from the others when rounded to the tenths place. Thus, the answer is:

Sprinter A
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