Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
To plot the graph of the function [tex]\( y = -\log(x - 2) + 3 \)[/tex], we need to follow a systematic approach. Let's break it down step-by-step:
1. Understanding the Function:
- The function involves a logarithmic term [tex]\(\log(x - 2)\)[/tex].
- The function is shifted horizontally by 2 units to the right due to the [tex]\(x - 2\)[/tex] inside the logarithm.
- The negative sign in front of the logarithm ([tex]\(-\log\)[/tex]) will reflect the graph across the x-axis.
- The "+3" outside of the logarithm shifts the graph vertically upwards by 3 units.
2. Domain of the Function:
- The logarithmic function [tex]\(\log(x - 2)\)[/tex] is defined when the argument is positive, i.e., [tex]\(x - 2 > 0\)[/tex].
- Therefore, the domain of the function is [tex]\( x > 2 \)[/tex].
3. Vertical Asymptote:
- As [tex]\( x \)[/tex] approaches 2 from the right ([tex]\( x \to 2^+ \)[/tex]), [tex]\( \log(x - 2) \to -\infty \)[/tex].
- Because of the negative sign, [tex]\(-\log(x - 2)\)[/tex] will tend to [tex]\(+\infty\)[/tex].
- Adding 3 to [tex]\(+\infty\)[/tex] means the function approaches [tex]\(+\infty\)[/tex].
- Therefore, there is a vertical asymptote at [tex]\( x = 2 \)[/tex].
4. Behavior as [tex]\( x \to \infty \)[/tex]:
- As [tex]\( x \)[/tex] increases, [tex]\( x - 2 \)[/tex] increases, thus [tex]\( \log(x - 2) \)[/tex] also increases.
- [tex]\(-\log(x - 2) \)[/tex] will become more negative.
- Adding 3 results in a large negative value.
- Therefore, as [tex]\( x \to \infty \)[/tex], [tex]\( y \to -\infty \)[/tex].
5. Key Points and Plotting:
- Let's find a few key points to help plot the graph:
- For [tex]\( x = 3 \)[/tex]:
[tex]\[ y = -\log(3 - 2) + 3 = -\log(1) + 3 = -0 + 3 = 3 \][/tex]
- For [tex]\( x = 4 \)[/tex]:
[tex]\[ y = -\log(4 - 2) + 3 = -\log(2) + 3 \approx -0.693 + 3 \approx 2.307 \][/tex]
- For [tex]\( x = 5 \)[/tex]:
[tex]\[ y = -\log(5 - 2) + 3 = -\log(3) + 3 \approx -1.099 + 3 \approx 1.901 \][/tex]
6. Sketching the Graph:
- Start by drawing a vertical asymptote at [tex]\( x = 2 \)[/tex].
- Plot the key points [tex]\((3, 3)\)[/tex], [tex]\((4, 2.307)\)[/tex], and [tex]\((5, 1.901)\)[/tex].
- Connect these points smoothly, showing that the function rapidly increases as [tex]\( x \to 2 \)[/tex] from the right and gradually decreases as [tex]\( x \to \infty \)[/tex].
Here's a sketch of the graph:
[tex]\[ \begin{array}{c|c} x & y\\ \hline 2^+ & +\infty \\ 3 & 3 \\ 4 & 2.307 \\ 5 & 1.901 \\ \vdots & \downarrow -\infty \end{array} \][/tex]
The graph of [tex]\( y = -\log(x - 2) + 3 \)[/tex] is a curve that:
- Has a vertical asymptote at [tex]\( x = 2 \)[/tex].
- Passes through the point (3, 3).
- Decreases as [tex]\( x \)[/tex] increases, eventually heading towards negative infinity as [tex]\( x \)[/tex] grows larger.
This detailed examination of the function allows us to visualize and interpret the behavior of its graph.
1. Understanding the Function:
- The function involves a logarithmic term [tex]\(\log(x - 2)\)[/tex].
- The function is shifted horizontally by 2 units to the right due to the [tex]\(x - 2\)[/tex] inside the logarithm.
- The negative sign in front of the logarithm ([tex]\(-\log\)[/tex]) will reflect the graph across the x-axis.
- The "+3" outside of the logarithm shifts the graph vertically upwards by 3 units.
2. Domain of the Function:
- The logarithmic function [tex]\(\log(x - 2)\)[/tex] is defined when the argument is positive, i.e., [tex]\(x - 2 > 0\)[/tex].
- Therefore, the domain of the function is [tex]\( x > 2 \)[/tex].
3. Vertical Asymptote:
- As [tex]\( x \)[/tex] approaches 2 from the right ([tex]\( x \to 2^+ \)[/tex]), [tex]\( \log(x - 2) \to -\infty \)[/tex].
- Because of the negative sign, [tex]\(-\log(x - 2)\)[/tex] will tend to [tex]\(+\infty\)[/tex].
- Adding 3 to [tex]\(+\infty\)[/tex] means the function approaches [tex]\(+\infty\)[/tex].
- Therefore, there is a vertical asymptote at [tex]\( x = 2 \)[/tex].
4. Behavior as [tex]\( x \to \infty \)[/tex]:
- As [tex]\( x \)[/tex] increases, [tex]\( x - 2 \)[/tex] increases, thus [tex]\( \log(x - 2) \)[/tex] also increases.
- [tex]\(-\log(x - 2) \)[/tex] will become more negative.
- Adding 3 results in a large negative value.
- Therefore, as [tex]\( x \to \infty \)[/tex], [tex]\( y \to -\infty \)[/tex].
5. Key Points and Plotting:
- Let's find a few key points to help plot the graph:
- For [tex]\( x = 3 \)[/tex]:
[tex]\[ y = -\log(3 - 2) + 3 = -\log(1) + 3 = -0 + 3 = 3 \][/tex]
- For [tex]\( x = 4 \)[/tex]:
[tex]\[ y = -\log(4 - 2) + 3 = -\log(2) + 3 \approx -0.693 + 3 \approx 2.307 \][/tex]
- For [tex]\( x = 5 \)[/tex]:
[tex]\[ y = -\log(5 - 2) + 3 = -\log(3) + 3 \approx -1.099 + 3 \approx 1.901 \][/tex]
6. Sketching the Graph:
- Start by drawing a vertical asymptote at [tex]\( x = 2 \)[/tex].
- Plot the key points [tex]\((3, 3)\)[/tex], [tex]\((4, 2.307)\)[/tex], and [tex]\((5, 1.901)\)[/tex].
- Connect these points smoothly, showing that the function rapidly increases as [tex]\( x \to 2 \)[/tex] from the right and gradually decreases as [tex]\( x \to \infty \)[/tex].
Here's a sketch of the graph:
[tex]\[ \begin{array}{c|c} x & y\\ \hline 2^+ & +\infty \\ 3 & 3 \\ 4 & 2.307 \\ 5 & 1.901 \\ \vdots & \downarrow -\infty \end{array} \][/tex]
The graph of [tex]\( y = -\log(x - 2) + 3 \)[/tex] is a curve that:
- Has a vertical asymptote at [tex]\( x = 2 \)[/tex].
- Passes through the point (3, 3).
- Decreases as [tex]\( x \)[/tex] increases, eventually heading towards negative infinity as [tex]\( x \)[/tex] grows larger.
This detailed examination of the function allows us to visualize and interpret the behavior of its graph.
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.