Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
To calculate the magnitude of the electrical force acting between two charges, we use Coulomb's Law. Coulomb's Law states that the magnitude of the force [tex]\( F \)[/tex] between two point charges is given by the formula:
[tex]\[ F = k \cdot \frac{|q_1 \cdot q_2|}{r^2} \][/tex]
where:
- [tex]\( k \)[/tex] is Coulomb's constant ([tex]\( 8.9875517873681764 \times 10^9 \, \text{N} \cdot \text{m}^2 / \text{C}^2 \)[/tex]),
- [tex]\( q_1 \)[/tex] and [tex]\( q_2 \)[/tex] are the magnitudes of the charges,
- [tex]\( r \)[/tex] is the distance between the charges.
Given:
- [tex]\( q_1 = 2.4 \times 10^{-8} \, \text{C} \)[/tex]
- [tex]\( q_2 = 1.8 \times 10^{-6} \, \text{C} \)[/tex]
- [tex]\( r = 0.008 \, \text{m} \)[/tex]
Step-by-step solution:
1. Calculate the product of the charges:
[tex]\[ |q_1 \times q_2| = (2.4 \times 10^{-8} \, \text{C}) \times (1.8 \times 10^{-6} \, \text{C}) \][/tex]
[tex]\[ = 4.32 \times 10^{-14} \, \text{C}^2 \][/tex]
2. Square the distance:
[tex]\[ r^2 = (0.008 \, \text{m})^2 \][/tex]
[tex]\[ = 6.4 \times 10^{-5} \, \text{m}^2 \][/tex]
3. Apply Coulomb's Law formula:
[tex]\[ F = \frac{8.9875517873681764 \times 10^9 \, \text{N} \cdot \text{m}^2 / \text{C}^2 \times 4.32 \times 10^{-14} \, \text{C}^2}{6.4 \times 10^{-5} \, \text{m}^2} \][/tex]
[tex]\[ = 6.0665974564735174 \, \text{N} \][/tex]
4. Round the result to the tenths place:
[tex]\[ F \approx 6.1 \, \text{N} \][/tex]
Therefore, the magnitude of the electrical force acting between the charges is [tex]\( 6.1 \, \text{N} \)[/tex], rounded to the tenths place.
[tex]\[ F = k \cdot \frac{|q_1 \cdot q_2|}{r^2} \][/tex]
where:
- [tex]\( k \)[/tex] is Coulomb's constant ([tex]\( 8.9875517873681764 \times 10^9 \, \text{N} \cdot \text{m}^2 / \text{C}^2 \)[/tex]),
- [tex]\( q_1 \)[/tex] and [tex]\( q_2 \)[/tex] are the magnitudes of the charges,
- [tex]\( r \)[/tex] is the distance between the charges.
Given:
- [tex]\( q_1 = 2.4 \times 10^{-8} \, \text{C} \)[/tex]
- [tex]\( q_2 = 1.8 \times 10^{-6} \, \text{C} \)[/tex]
- [tex]\( r = 0.008 \, \text{m} \)[/tex]
Step-by-step solution:
1. Calculate the product of the charges:
[tex]\[ |q_1 \times q_2| = (2.4 \times 10^{-8} \, \text{C}) \times (1.8 \times 10^{-6} \, \text{C}) \][/tex]
[tex]\[ = 4.32 \times 10^{-14} \, \text{C}^2 \][/tex]
2. Square the distance:
[tex]\[ r^2 = (0.008 \, \text{m})^2 \][/tex]
[tex]\[ = 6.4 \times 10^{-5} \, \text{m}^2 \][/tex]
3. Apply Coulomb's Law formula:
[tex]\[ F = \frac{8.9875517873681764 \times 10^9 \, \text{N} \cdot \text{m}^2 / \text{C}^2 \times 4.32 \times 10^{-14} \, \text{C}^2}{6.4 \times 10^{-5} \, \text{m}^2} \][/tex]
[tex]\[ = 6.0665974564735174 \, \text{N} \][/tex]
4. Round the result to the tenths place:
[tex]\[ F \approx 6.1 \, \text{N} \][/tex]
Therefore, the magnitude of the electrical force acting between the charges is [tex]\( 6.1 \, \text{N} \)[/tex], rounded to the tenths place.
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.