Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
To determine whether each function is odd, we can use the definition of an odd function. A function [tex]\( f(x) \)[/tex] is considered odd if [tex]\( f(-x) = -f(x) \)[/tex] for all [tex]\( x \)[/tex] in the domain of [tex]\( f \)[/tex].
Let's check each function step-by-step:
1. Function [tex]\( f(x) = x^3 - x^2 \)[/tex]:
Calculate [tex]\( f(-x) \)[/tex] and compare it with [tex]\( -f(x) \)[/tex]:
[tex]\[ f(-x) = (-x)^3 - (-x)^2 = -x^3 - x^2 \][/tex]
[tex]\[ -f(x) = -(x^3 - x^2) = -x^3 + x^2 \][/tex]
Since [tex]\( f(-x) \neq -f(x) \)[/tex] (because [tex]\( -x^3 - x^2 \neq -x^3 + x^2 \)[/tex]), the function [tex]\( f(x) = x^3 - x^2 \)[/tex] is not odd.
2. Function [tex]\( f(x) = x^5 - 3x^3 + 2x \)[/tex]:
Calculate [tex]\( f(-x) \)[/tex] and compare it with [tex]\( -f(x) \)[/tex]:
[tex]\[ f(-x) = (-x)^5 - 3(-x)^3 + 2(-x) = -x^5 + 3x^3 - 2x \][/tex]
[tex]\[ -f(x) = -(x^5 - 3x^3 + 2x) = -x^5 + 3x^3 - 2x \][/tex]
Since [tex]\( f(-x) = -f(x) \)[/tex] (because [tex]\( -x^5 + 3x^3 - 2x = -x^5 + 3x^3 - 2x \)[/tex]), the function [tex]\( f(x) = x^5 - 3x^3 + 2x \)[/tex] is odd.
3. Function [tex]\( f(x) = 4x + 9 \)[/tex]:
Calculate [tex]\( f(-x) \)[/tex] and compare it with [tex]\( -f(x) \)[/tex]:
[tex]\[ f(-x) = 4(-x) + 9 = -4x + 9 \][/tex]
[tex]\[ -f(x) = -(4x + 9) = -4x - 9 \][/tex]
Since [tex]\( f(-x) \neq -f(x) \)[/tex] (because [tex]\( -4x + 9 \neq -4x - 9 \)[/tex]), the function [tex]\( f(x) = 4x + 9 \)[/tex] is not odd.
4. Function [tex]\( f(x) = \frac{1}{x} \)[/tex]:
Calculate [tex]\( f(-x) \)[/tex] and compare it with [tex]\( -f(x) \)[/tex]:
[tex]\[ f(-x) = \frac{1}{-x} = -\frac{1}{x} \][/tex]
[tex]\[ -f(x) = -\left( \frac{1}{x} \right) = -\frac{1}{x} \][/tex]
Since [tex]\( f(-x) = -f(x) \)[/tex] (because [tex]\( -\frac{1}{x} = -\frac{1}{x} \)[/tex]), the function [tex]\( f(x) = \frac{1}{x} \)[/tex] is odd.
Therefore, the odd functions among the given list are:
[tex]\[ f(x) = x^5 - 3x^3 + 2x \][/tex]
and
[tex]\[ f(x) = \frac{1}{x} \][/tex]
This matches the results [tex]\( (False, True, False, True) \)[/tex] for the respective functions.
Let's check each function step-by-step:
1. Function [tex]\( f(x) = x^3 - x^2 \)[/tex]:
Calculate [tex]\( f(-x) \)[/tex] and compare it with [tex]\( -f(x) \)[/tex]:
[tex]\[ f(-x) = (-x)^3 - (-x)^2 = -x^3 - x^2 \][/tex]
[tex]\[ -f(x) = -(x^3 - x^2) = -x^3 + x^2 \][/tex]
Since [tex]\( f(-x) \neq -f(x) \)[/tex] (because [tex]\( -x^3 - x^2 \neq -x^3 + x^2 \)[/tex]), the function [tex]\( f(x) = x^3 - x^2 \)[/tex] is not odd.
2. Function [tex]\( f(x) = x^5 - 3x^3 + 2x \)[/tex]:
Calculate [tex]\( f(-x) \)[/tex] and compare it with [tex]\( -f(x) \)[/tex]:
[tex]\[ f(-x) = (-x)^5 - 3(-x)^3 + 2(-x) = -x^5 + 3x^3 - 2x \][/tex]
[tex]\[ -f(x) = -(x^5 - 3x^3 + 2x) = -x^5 + 3x^3 - 2x \][/tex]
Since [tex]\( f(-x) = -f(x) \)[/tex] (because [tex]\( -x^5 + 3x^3 - 2x = -x^5 + 3x^3 - 2x \)[/tex]), the function [tex]\( f(x) = x^5 - 3x^3 + 2x \)[/tex] is odd.
3. Function [tex]\( f(x) = 4x + 9 \)[/tex]:
Calculate [tex]\( f(-x) \)[/tex] and compare it with [tex]\( -f(x) \)[/tex]:
[tex]\[ f(-x) = 4(-x) + 9 = -4x + 9 \][/tex]
[tex]\[ -f(x) = -(4x + 9) = -4x - 9 \][/tex]
Since [tex]\( f(-x) \neq -f(x) \)[/tex] (because [tex]\( -4x + 9 \neq -4x - 9 \)[/tex]), the function [tex]\( f(x) = 4x + 9 \)[/tex] is not odd.
4. Function [tex]\( f(x) = \frac{1}{x} \)[/tex]:
Calculate [tex]\( f(-x) \)[/tex] and compare it with [tex]\( -f(x) \)[/tex]:
[tex]\[ f(-x) = \frac{1}{-x} = -\frac{1}{x} \][/tex]
[tex]\[ -f(x) = -\left( \frac{1}{x} \right) = -\frac{1}{x} \][/tex]
Since [tex]\( f(-x) = -f(x) \)[/tex] (because [tex]\( -\frac{1}{x} = -\frac{1}{x} \)[/tex]), the function [tex]\( f(x) = \frac{1}{x} \)[/tex] is odd.
Therefore, the odd functions among the given list are:
[tex]\[ f(x) = x^5 - 3x^3 + 2x \][/tex]
and
[tex]\[ f(x) = \frac{1}{x} \][/tex]
This matches the results [tex]\( (False, True, False, True) \)[/tex] for the respective functions.
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.