Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
To determine the correct chemical reaction for fluorine gas reacting with calcium metal at high temperatures to produce calcium fluoride powder, we need to examine the given options step-by-step:
1. [tex]$F_2(l) + Na(s) \longrightarrow NaF_2(s)$[/tex]
This reaction involves liquid fluorine ([tex]$F_2(l)$[/tex]) and sodium metal (Na). The product is sodium fluoride ([tex]$NaF_2$[/tex]) in solid form. Since the reactants are incorrect (lithium instead of gas and sodium instead of calcium), this equation cannot be correct.
2. [tex]$F_2(o) + Ca(c) \longrightarrow CaF_2(m)$[/tex]
This reaction is supposed to involve fluorine in an unknown state ('o') and solid calcium metal ('c'). The product is calcium fluoride ('m'). However, 'o' and 'm' are not standard states or forms in chemical notation, making this option incorrect.
3. [tex]$F_2(g) + Na(s) \xrightarrow{\Delta} NaF_2(l)$[/tex]
Here, fluorine gas ([tex]$F_2(g)$[/tex]) reacts with solid sodium metal (Na) at high temperatures (indicated by [tex]$\Delta$[/tex]), producing liquid sodium fluoride ([tex]$NaF_2(l)$[/tex]). Sodium is not the correct reactant, so this option is invalid for this reaction.
4. [tex]$F_2(g) + Ca(s) \xrightarrow{\Delta} CaF_2(s)$[/tex]
This reaction involves fluorine gas ([tex]$F_2(g)$[/tex]) and solid calcium metal (Ca) reacting at high temperatures (indicated by [tex]$\Delta$[/tex]) to produce solid calcium fluoride ([tex]$CaF_2$[/tex]). This matches precisely with the given problem statement, as it correctly identifies the reactants (fluorine gas and calcium metal) and the product (calcium fluoride powder).
Therefore, the correct formula equation for the reaction of fluorine gas with calcium metal to produce calcium fluoride is:
[tex]\[ \boxed{F_2(g) + Ca(s) \xrightarrow{\Delta} CaF_2(s)} \][/tex]
1. [tex]$F_2(l) + Na(s) \longrightarrow NaF_2(s)$[/tex]
This reaction involves liquid fluorine ([tex]$F_2(l)$[/tex]) and sodium metal (Na). The product is sodium fluoride ([tex]$NaF_2$[/tex]) in solid form. Since the reactants are incorrect (lithium instead of gas and sodium instead of calcium), this equation cannot be correct.
2. [tex]$F_2(o) + Ca(c) \longrightarrow CaF_2(m)$[/tex]
This reaction is supposed to involve fluorine in an unknown state ('o') and solid calcium metal ('c'). The product is calcium fluoride ('m'). However, 'o' and 'm' are not standard states or forms in chemical notation, making this option incorrect.
3. [tex]$F_2(g) + Na(s) \xrightarrow{\Delta} NaF_2(l)$[/tex]
Here, fluorine gas ([tex]$F_2(g)$[/tex]) reacts with solid sodium metal (Na) at high temperatures (indicated by [tex]$\Delta$[/tex]), producing liquid sodium fluoride ([tex]$NaF_2(l)$[/tex]). Sodium is not the correct reactant, so this option is invalid for this reaction.
4. [tex]$F_2(g) + Ca(s) \xrightarrow{\Delta} CaF_2(s)$[/tex]
This reaction involves fluorine gas ([tex]$F_2(g)$[/tex]) and solid calcium metal (Ca) reacting at high temperatures (indicated by [tex]$\Delta$[/tex]) to produce solid calcium fluoride ([tex]$CaF_2$[/tex]). This matches precisely with the given problem statement, as it correctly identifies the reactants (fluorine gas and calcium metal) and the product (calcium fluoride powder).
Therefore, the correct formula equation for the reaction of fluorine gas with calcium metal to produce calcium fluoride is:
[tex]\[ \boxed{F_2(g) + Ca(s) \xrightarrow{\Delta} CaF_2(s)} \][/tex]
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.