Draw the Lewis electron dot structure for [tex]$H_3O^+$[/tex].

What is the VSEPR shape of this particle?

Question

10-07-2024
Chemistry

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Draw the Lewis electron dot structure for [tex]$H_3O^+$[/tex].

What is the VSEPR shape of this particle?

Sagot :

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GinnyAnswer GinnyAnswer · Answer 1 · 2024-07-10T10:30:18-04:00

Final answer:

The Lewis structure for H3O+ involves one oxygen atom and three hydrogen atoms, with a total of 9 valence electrons. The VSEPR shape of H3O+ is trigonal pyramidal due to the electron geometry and molecular shape.

Explanation:

Lewis Electron Dot Structure for H3O+: The Lewis structure for H3O+ consists of one oxygen atom with three hydrogen atoms attached to it. Oxygen has 6 valence electrons, and each hydrogen contributes one, making a total of 9 valence electrons. The structure will have three lone pairs on oxygen and three single bonds to hydrogen.

VSEPR Shape of H3O+: The VSEPR shape of H3O+ is trigonal pyramidal. In this shape, the oxygen atom is at the center, with three bonding pairs and one lone pair of electrons, creating a tetrahedral electron geometry and a trigonal pyramidal molecular shape.

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