Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
To solve this problem, we first need to understand the properties and equation format of parallel lines and how to use the given point. The given equation is:
[tex]\[ y - 1 = -2(x - 4) \][/tex]
This is in point-slope form of the equation of a line, which is generally given by:
[tex]\[ y - y_1 = m(x - x_1) \][/tex]
where [tex]\( m \)[/tex] is the slope and [tex]\((x_1, y_1)\)[/tex] is a point on the line.
### Step 1: Determine the Slope of the Given Line
The slope [tex]\( m \)[/tex] of the given line can be directly read from the given equation. Comparing with the point-slope form, we see that:
[tex]\[ y - 1 = -2(x - 4) \][/tex]
By comparing, [tex]\( m = -2 \)[/tex].
### Step 2: Use the Point Through Which the New Line Should Pass
The new line that is parallel will have the same slope [tex]\( m \)[/tex]. The given point through which this new line must pass is [tex]\( (4, 1) \)[/tex].
### Step 3: Form the Point-Slope Equation for the New Line
Substitute the slope [tex]\( m = -2 \)[/tex] and the point [tex]\((4, 1)\)[/tex] into the point-slope form of the line equation:
[tex]\[ y - y_1 = m(x - x_1) \][/tex]
Here, [tex]\( y_1 = 1 \)[/tex] and [tex]\( x_1 = 4 \)[/tex]. Substituting these values, we get:
[tex]\[ y - 1 = -2(x - 4) \][/tex]
### Conclusion:
The equation of the line that is parallel to the given line [tex]\( y - 1 = -2(x - 4) \)[/tex] and passes through the point [tex]\((4, 1)\)[/tex] is:
[tex]\[ y - 1 = -2(x - 4) \][/tex]
Looking at the choices provided:
1. [tex]\( y - 1 = -2(x - 4) \)[/tex]
2. [tex]\( y - 1 = -\frac{1}{2}(x - 4) \)[/tex]
3. [tex]\( y - 1 = \frac{1}{2}(x - 4) \)[/tex]
4. [tex]\( y - 1 = 2(x - 4) \)[/tex]
The correct equation is the first one:
[tex]\[ y - 1 = -2(x - 4) \][/tex]
Hence, the correct choice is [tex]\( \boxed{1} \)[/tex].
[tex]\[ y - 1 = -2(x - 4) \][/tex]
This is in point-slope form of the equation of a line, which is generally given by:
[tex]\[ y - y_1 = m(x - x_1) \][/tex]
where [tex]\( m \)[/tex] is the slope and [tex]\((x_1, y_1)\)[/tex] is a point on the line.
### Step 1: Determine the Slope of the Given Line
The slope [tex]\( m \)[/tex] of the given line can be directly read from the given equation. Comparing with the point-slope form, we see that:
[tex]\[ y - 1 = -2(x - 4) \][/tex]
By comparing, [tex]\( m = -2 \)[/tex].
### Step 2: Use the Point Through Which the New Line Should Pass
The new line that is parallel will have the same slope [tex]\( m \)[/tex]. The given point through which this new line must pass is [tex]\( (4, 1) \)[/tex].
### Step 3: Form the Point-Slope Equation for the New Line
Substitute the slope [tex]\( m = -2 \)[/tex] and the point [tex]\((4, 1)\)[/tex] into the point-slope form of the line equation:
[tex]\[ y - y_1 = m(x - x_1) \][/tex]
Here, [tex]\( y_1 = 1 \)[/tex] and [tex]\( x_1 = 4 \)[/tex]. Substituting these values, we get:
[tex]\[ y - 1 = -2(x - 4) \][/tex]
### Conclusion:
The equation of the line that is parallel to the given line [tex]\( y - 1 = -2(x - 4) \)[/tex] and passes through the point [tex]\((4, 1)\)[/tex] is:
[tex]\[ y - 1 = -2(x - 4) \][/tex]
Looking at the choices provided:
1. [tex]\( y - 1 = -2(x - 4) \)[/tex]
2. [tex]\( y - 1 = -\frac{1}{2}(x - 4) \)[/tex]
3. [tex]\( y - 1 = \frac{1}{2}(x - 4) \)[/tex]
4. [tex]\( y - 1 = 2(x - 4) \)[/tex]
The correct equation is the first one:
[tex]\[ y - 1 = -2(x - 4) \][/tex]
Hence, the correct choice is [tex]\( \boxed{1} \)[/tex].
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.