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Ramanuj walked from "Tower A" to "Tower B" in the East for 10 feet. Then he turned to the right and walked 3 feet. Again, he turned to the right and walked 14 feet. How far is he from Tower A?

Sagot :

GinnyAnswer

Final answer:

Using the Pythagorean theorem, we find that Ramanuj is approximately 24.2 feet away from Tower A after walking east and north.


Explanation:

To find the distance from Tower A, we can use the concept of Pythagorean theorem in a right-angled triangle.

After walking 10 feet East, 3 feet North, and 14 feet East from Tower B, the horizontal distance from Tower A is 10 + 14 = 24 feet, and the vertical distance is 3 feet.

Therefore, the distance from Tower A is the hypotenuse of a right triangle with legs 24 feet and 3 feet, which can be calculated using the formula: distance = √(242 + 32) = √(576 + 9) = √585 = 24.2 feet(hypotenuse).


Learn more about Distance calculation using the Pythagorean theorem here:

https://brainly.com/question/29260362


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