Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
To simplify the expression [tex]\(\sqrt[3]{125 x^2 y^7}\)[/tex] using rational exponent properties and the definition of a radical in terms of exponents, we can break it down step-by-step as follows:
[tex]\[ \begin{array}{|l|l|} \hline \text{Step 1} & \sqrt[3]{125 x^2 y^7} \\ \hline \text{Step 2} & 125^{1/3} (x^2)^{1/3} (y^7)^{1/3} \\ \hline \text{Step 3} & 5 \cdot x^{2/3} \cdot y^{7/3} \\ \hline \text{Step 4} & 5 \cdot x^{2/3} \cdot y^{2 + 1/3} \\ \hline \text{Step 5} & 5 \cdot x^{2/3} \cdot y^2 \cdot y^{1/3} \\ \hline \text{Step 6} & 5y^2 \cdot x^{2/3} \cdot y^{1/3} \\ \hline \text{Step 7} & 5y^2 \cdot xy^{1/3} \\ \hline \end{array} \][/tex]
Explanation of each step:
- Step 1: Start with the given expression [tex]\(\sqrt[3]{125 x^2 y^7}\)[/tex].
- Step 2: Express the cube root in terms of rational exponents: [tex]\(125^{1/3} (x^2)^{1/3} (y^7)^{1/3}\)[/tex].
- Step 3: Simplify each term separately. [tex]\(125^{1/3} = 5\)[/tex], [tex]\((x^2)^{1/3} = x^{2/3}\)[/tex], [tex]\((y^7)^{1/3} = y^{7/3}\)[/tex].
- Step 4: Decompose [tex]\(y^{7/3}\)[/tex] into [tex]\(y^2 \cdot y^{1/3}\)[/tex] by writing [tex]\(7/3\)[/tex] as [tex]\(2 + 1/3\)[/tex].
- Step 5: Combine the terms to separate out [tex]\(y^2\)[/tex] and [tex]\(y^{1/3}\)[/tex].
- Step 6: Rewrite the combined term for clarity: [tex]\(5y^2 \cdot x^{2/3} \cdot y^{1/3}\)[/tex].
- Step 7: Re-arrange the terms, if needed, for standard form: [tex]\(5y^2 \cdot x^{2/3} \cdot y^{1/3}\)[/tex].
[tex]\[ \begin{array}{|l|l|} \hline \text{Step 1} & \sqrt[3]{125 x^2 y^7} \\ \hline \text{Step 2} & 125^{1/3} (x^2)^{1/3} (y^7)^{1/3} \\ \hline \text{Step 3} & 5 \cdot x^{2/3} \cdot y^{7/3} \\ \hline \text{Step 4} & 5 \cdot x^{2/3} \cdot y^{2 + 1/3} \\ \hline \text{Step 5} & 5 \cdot x^{2/3} \cdot y^2 \cdot y^{1/3} \\ \hline \text{Step 6} & 5y^2 \cdot x^{2/3} \cdot y^{1/3} \\ \hline \text{Step 7} & 5y^2 \cdot xy^{1/3} \\ \hline \end{array} \][/tex]
Explanation of each step:
- Step 1: Start with the given expression [tex]\(\sqrt[3]{125 x^2 y^7}\)[/tex].
- Step 2: Express the cube root in terms of rational exponents: [tex]\(125^{1/3} (x^2)^{1/3} (y^7)^{1/3}\)[/tex].
- Step 3: Simplify each term separately. [tex]\(125^{1/3} = 5\)[/tex], [tex]\((x^2)^{1/3} = x^{2/3}\)[/tex], [tex]\((y^7)^{1/3} = y^{7/3}\)[/tex].
- Step 4: Decompose [tex]\(y^{7/3}\)[/tex] into [tex]\(y^2 \cdot y^{1/3}\)[/tex] by writing [tex]\(7/3\)[/tex] as [tex]\(2 + 1/3\)[/tex].
- Step 5: Combine the terms to separate out [tex]\(y^2\)[/tex] and [tex]\(y^{1/3}\)[/tex].
- Step 6: Rewrite the combined term for clarity: [tex]\(5y^2 \cdot x^{2/3} \cdot y^{1/3}\)[/tex].
- Step 7: Re-arrange the terms, if needed, for standard form: [tex]\(5y^2 \cdot x^{2/3} \cdot y^{1/3}\)[/tex].
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.