Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Factor completely [tex][tex]$9x^3 + 36x^2 - x - 4$[/tex][/tex].

A. [tex]$(3x + 4)(3x - 4)(x + 1)$[/tex]

B. [tex]$(3x + 1)(3x - 1)(x + 4)$[/tex]

C. [tex][tex]$\left(9x^2 - 1\right)(x + 4)$[/tex][/tex]

D. [tex]$(3x + 1)(3x - 1)(x - 4)$[/tex]


Sagot :

Let's factor the polynomial [tex]\(9x^3 + 36x^2 - x - 4\)[/tex] completely. We seek to express it as a product of simpler polynomials.

Given: [tex]\(9x^3 + 36x^2 - x - 4\)[/tex]

We'll proceed step-by-step to factorize it.

1. Identify Possible Rational Roots:
For a polynomial [tex]\(ax^n + bx^{n-1} + \ldots + k\)[/tex], possible rational roots can be factors of the constant term divided by factors of the leading coefficient. In this case, constant term = [tex]\(-4\)[/tex] and leading coefficient = [tex]\(9\)[/tex].

2. Trial and Error for Rational Roots:
We test various potential rational roots:
- Factors of [tex]\(-4\)[/tex] are [tex]\(\pm 1, \pm 2, \pm 4\)[/tex].
- Factors of [tex]\(9\)[/tex] are [tex]\(\pm 1, \pm 3, \pm 9\)[/tex].

We test each combination, for example, [tex]\(\pm \frac{1}{1}, \pm \frac{1}{3}, \pm \frac{1}{9}, \pm \frac{2}{1}, \pm \frac{4}{1}, etc.\)[/tex].

3. Synthetic Division:
We find through synthetic division or evaluating the polynomial that [tex]\(x = -4\)[/tex] is a root.

Dividing [tex]\(9x^3 + 36x^2 - x - 4\)[/tex] by [tex]\((x + 4)\)[/tex], we obtain the quotient [tex]\((3x^2 + 3x - 1)\)[/tex].

4. Factor the Quadratic Polynomial [tex]\(3x^2 + 3x - 1\)[/tex]:
Next, we factorize [tex]\(3x^2 + 3x - 1\)[/tex]. Using the quadratic formula [tex]\(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)[/tex], we find:
[tex]\[ x = \frac{-3 \pm \sqrt{(3)^2 - 4(3)(-1)}}{2(3)} = \frac{-3 \pm \sqrt{9 + 12}}{6} = \frac{-3 \pm \sqrt{21}}{6} = \frac{-3 \pm 3\sqrt{21}}{6} = \frac{-3 \pm \sqrt{21}}{6} = \frac{-1 \pm \sqrt{21}}{6} \][/tex]
Therefore, [tex]\(3x^2 + 3x - 1\)[/tex] factors into [tex]\((3x - 1)(x + \frac{1}{3}) \)[/tex].

However, since we are dealing with integers in the factors, rewritting [tex]\(x + \frac{1}{3}\)[/tex] in the integer factor form, we get [tex]\((3x-1)\)[/tex] and [tex]\((x+4)\)[/tex].

Putting it all together, the polynomial [tex]\(9x^3 + 36x^2 - x - 4\)[/tex] factors completely as:
[tex]\[ (3x - 1)(3x + 1)(x + 4) \][/tex]

So, the correct answer is:
[tex]\[ (3x + 1)(3x - 1)(x + 4) \][/tex]
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.