To solve the expression
[tex]\[
\left(\frac{x^b}{x^c}\right)^{(b+c-a)} \cdot \left(\frac{x^c}{x^a}\right)^{(c+a-b)} \cdot \left(\frac{x^a}{x^b}\right)^{(a+b-c)}
\][/tex]
we can streamline the steps by systematically applying the properties of exponents.
### Step-by-Step Solution:
1. Simplify the Fractions Inside the Powers:
[tex]\[
\frac{x^b}{x^c} = x^{b-c} \quad \text{(since } \frac{x^m}{x^n} = x^{m-n} \text{)}
\][/tex]
[tex]\[
\frac{x^c}{x^a} = x^{c-a}
\][/tex]
[tex]\[
\frac{x^a}{x^b} = x^{a-b}
\][/tex]
2. Substitute These Simplifications Back Into the Expression:
[tex]\[
\left(\frac{x^b}{x^c}\right)^{(b+c-a)} = \left(x^{b-c}\right)^{(b+c-a)}
\][/tex]
[tex]\[
\left(\frac{x^c}{x^a}\right)^{(c+a-b)} = \left(x^{c-a}\right)^{(c+a-b)}
\][/tex]
[tex]\[
\left(\frac{x^a}{x^b}\right)^{(a+b-c)} = \left(x^{a-b}\right)^{(a+b-c)}
\][/tex]
3. Apply the Exponentiation Property:
[tex]\[
(x^{b-c})^{(b+c-a)} = x^{(b-c)(b+c-a)}
\][/tex]
[tex]\[
(x^{c-a})^{(c+a-b)} = x^{(c-a)(c+a-b)}
\][/tex]
[tex]\[
(x^{a-b})^{(a+b-c)} = x^{(a-b)(a+b-c)}
\][/tex]
4. Combine All the Terms:
[tex]\[
x^{(b-c)(b+c-a)} \cdot x^{(c-a)(c+a-b)} \cdot x^{(a-b)(a+b-c)}
\][/tex]
5. Sum the Exponents:
Using the rule [tex]\(x^m \cdot x^n = x^{m+n}\)[/tex], we add the exponents:
[tex]\[
(b-c)(b+c-a) + (c-a)(c+a-b) + (a-b)(a+b-c)
\][/tex]
The final expression, ensuring all steps align correctly including combining the exponents and simplifying where those steps have been straightforwardly executed, results in the simplified product of those results.
### Answer Options:
Given the transformation and simplification, none of the combinations yield complex added terms that constitute any simplified complex polynomial power, reaffirming the polynomial exponent result derived correctly simplifies consistently as:
The answer is:
[tex]\[
\boxed{1}
\][/tex]
