Answered

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The gas inside a large engine cylinder initially has a pressure of 105 kilopascals and a volume of 2.031 liters. If the gas is compressed at constant temperature to a volume of 0.356 liter, what is its new pressure? The pressure of the compressed gas is kilopascals.

Sagot :

Answer:

[tex]\rm P_2=599.031\:kPa[/tex]

Explanation:

Boyle's Law

Boyle's law is one of the ideal gas laws. This one deals with pressure and volume,

                                            [tex]P_1V_1=P_2V_2[/tex],

P is pressure (kilopascals; kPa), V is volume (liters; L) and the subscripts represent the initial and final quantities.

This law implies an inverse relationship between the two quantities.

[tex]\hrulefill[/tex]

Solving the Problem

We're given the initial pressure and volume, and the final volume. We're asked to find the final pressure.

After plugging in all the known values, we can rearrange for the missing one!

                            [tex]\rm (105\: kPa)(2.031\:L)=P_2(0.356\:L)[/tex]

                        [tex]\rm \dfrac{(105\:kPa)(2.031\:L)}{(0.356\: L)} =P_2=599.031\:kPa[/tex]

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