zoedeweese
Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

In triangle DEF, DF=22 and angle F=45. Find the length of a leg. Leave your answer in simplest radical form.

Options:
1.) sqrt2
2.) sqrt11
3.) 11sqrt2
4.) sqrt22
​

In Triangle DEF DF22 And Angle F45 Find The Length Of A Leg Leave Your Answer In Simplest Radical FormOptions1 Sqrt22 Sqrt113 11sqrt24 Sqrt22 class=

Sagot :

sqrt{2} = [tex]\sqrt{2}[/tex]

Given that

DF is the hypotenuse, we have:

DF = x sqrt{2}

x is the length of each leg.

Since DF = 22, we can setup the equation:

22 = x sqrt{2}

To simplify, we rationalize the denominator:

x = 22/[tex]\sqrt{2}[/tex] * sqrt{2} / sqrt{2} = 22sqrt{2}/2 = 11sqrt{2}

Thus, the length of each leg is:

11[tex]\sqrt{2}[/tex]

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.