Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Ask your questions and receive precise answers from experienced professionals across different disciplines. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Simplify the expression:
[tex]\[ xy \left(x^2 + x - 3\right) \][/tex]


Sagot :

Sure! Let's break down the expression [tex]\( x y(x^2 + x - 3) \)[/tex] step by step.

### Step 1: Understand the Expression
The given expression is [tex]\( x y(x^2 + x - 3) \)[/tex]. This is a product of [tex]\( xy \)[/tex] and the polynomial [tex]\( x^2 + x - 3 \)[/tex].

### Step 2: Distribute [tex]\( x \)[/tex] over the Polynomial
First, we can distribute [tex]\( x \)[/tex] in [tex]\( xy(x^2 + x - 3) \)[/tex]:

[tex]\[ x \cdot (x^2 + x - 3) = x^3 + x^2 x - 3x \][/tex]

### Step 3: Combine with [tex]\( y \)[/tex]
Now multiply the entire expression by [tex]\( y \)[/tex]:

[tex]\[ y \cdot (x^3 + x^2 + x - 3x) = y x^3 + y x^2 + y x - 3 y x \][/tex]

### Step 4: Combine like terms
Rewriting the expression for better clarity:

[tex]\[ x y(x^3 + x^2 + x - 3) \][/tex]

In this, we see how each term [tex]\( x \)[/tex] in [tex]\( x^2 + x - 3 \)[/tex] has been multiplied by both [tex]\( x \)[/tex] and [tex]\( y \)[/tex].

### Final Expression
Thus, the expression [tex]\( x y(x^2 + x - 3) \)[/tex] simplifies directly to the expanded form:

[tex]\[ x y(x^2 + x - 3) \][/tex]

So, the final simplified form of [tex]\( x y (x^2 + x - 3) \)[/tex] is indeed:

[tex]\[ x y(x^2 + x - 3) \][/tex]

This reproduces the final result clearly and steps you through the expression manipulation.
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.